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3 years ago

Find five pairs of whole numbers, such that when they are inserted into the equation below, the solution is 3.

Mathematics

1 answer:

Vaselesa [24]3 years ago

3 0

For this case we have, according to the statement, the following equation:

$x + y = 3$

We must find 5 pairs of integers that meet the equation:

$(-1,4)\\-1 + 4 = -1 + 4 = 3$

$(1,2)\\1 + 2 = 3$

$(7, -4)\\7 + (- 4) = 7-4 = 3$

$(3,0)\\3 + 0 = 3$

$(5, -2)\\5 + (- 2) = 5-2 = 3$

Answer:

The pairs of integers can be:

$(-1,4)\\(1,2)\\(7, -4)\\(3,0)\\(5,-2)\\$

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Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

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