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Zinaida [17]
4 years ago
7

How many solutions exist the mixed-degree system graphed below​

Mathematics
2 answers:
nalin [4]4 years ago
8 0

Answer:

I dont know if this is correct but maybe there is 2 solutions in this problem.

Dont put it as your answer if is incorrect!!!!!!!!

Step-by-step explanation:

zzz [600]4 years ago
8 0

Answer:

Two solutions

Step-by-step explanation:

The number of answers in system = number of intersections when graphed.

Knowing that, looking at the graph shows that there are two intersections. We also can see that there can not be any more intersections when we expand the graph.

So, two solutions.

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Will give brainlst <br> Have a nice day
Zolol [24]

Step-by-step explanation:

9) given

12x = 4(x + 2) + 20 \\ 12x = 4x + 8 + 20 \\ 8x = 28 \\ x = 28 \div 8 \\  = 3.5

10)standard form equation: y=mx+c

where m = slope and c = y-intercept

given m = 8, c = 12,

equation of line :

y = 8x + 12

4 0
3 years ago
If p:q = 5;2 and q:r = 3:4, what is the ratio of p to r?
igor_vitrenko [27]
5:4 since p is equal to 5 and r is equal to 4
5 0
3 years ago
The volume of a cone with a radius of 7 cm is 147 pi cubic centimeters. Which expression can be used to find h, the height of th
Aleks04 [339]

volume(V)=147cm^3

also,

v=1/3×3.14×7^2×h

or, 147×3=3.14×49×h

or, (441)/(3.14×49)=h

or, h=2.87cm

3 0
3 years ago
Read 2 more answers
How do I solve this, pretty urgent please. ​
Andreas93 [3]

Answer:

  • 1

Step-by-step explanation:

<u>Substitute:</u>

  • x^{0.5} = y

<u>Then the expression becomes:</u>

  • (\dfrac{1+y^3}{1-y+y^2}-y) \dfrac{1-y^2}{1-y}  -y=\\
  • (\dfrac{(1+y)(1-y+y^2)}{1-y+y^2}-y) \dfrac{(1-y)(1+y)}{1-y}  -y=
  • (1+y-y)(1+y)-y=
  • 1(1+y)-y=
  • 1+y-y=
  • 1

The result is 1 regardless the value of x other than 1.

5 0
3 years ago
A bow is made out of 5/8 yards of red ribbon and 3/4 yards of blue ribbon. What is the unit rate of red ribbon to blue ribbon?
r-ruslan [8.4K]
Divide 3/4 by 5/8

= 6/8 / 5/8  = 6/8 * 8/5 = 6/5

Unit rate is  1 to 6/5  =  = 1  to 1.2
8 0
3 years ago
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