Ask question

Ask question

All categories

adelina 88 [10]

2 years ago

15

you have 3 boxes, one "strawberries";one "mentos" and one "mixed".But you know that all the labels are in incorrect order .How d

o you know witch is witch?

1 answer:

frozen [14]2 years ago

5 0

Answer:

If you dump all of them into one box then you know that one is the mixed

You might be interested in

Olegator [25]

Hope this helps somewhat

7 0

2 years ago

Help I need this done ASAP anyone know how to solve this

ludmilkaskok [199]

Equation~ 5b + (2b - 4) + (3b -6)= 180.

4 0

2 years ago

HELP PLS MARKING BRAINLEIST TO CORRECT ANSWER

Andreyy89

Answer:

6/3=2

Step-by-step explanation:

its very easy pls give brainliest

3 0

2 years ago

Read 2 more answers

1/2 of 5 for my Khan Academy answer

Tems11 [23]

Answer:

...

Step-by-step explanation:

7 0

2 years ago

Find the vertices and foci of the hyperbola with equation quantity x minus 5 squared divided by 144 minus the quantity of y minu

Serjik [45]

$\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases}\\\\ -------------------------------$

$\bf \cfrac{(x-5)^2}{144}-\cfrac{(y-4)^2}{81}=1\implies \cfrac{(x-5)^2}{12^2}-\cfrac{(y-4)^2}{9^2}=1 \\\\\\ \begin{cases} h=5\\ k=4\\ a=12\\ b=9 \end{cases}\implies c=\sqrt{144+81}\implies c=\sqrt{225}\implies c=15 \\\\\\ \stackrel{center}{(5,4)}\qquad \qquad \stackrel{\textit{because is a horizontal traverse hyperbola}}{\stackrel{foci}{\stackrel{(5\pm 15,4)}{(20,4),(-10,4)}}\qquad \qquad \stackrel{vertices}{\stackrel{(5\pm 12,4)}{(17,4),(-7,4)}}}$

5 0

2 years ago