Solve the system of linear equations by substitution.
1 answer:
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The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
Answer:
92 ft
Step-by-step explanation:
Assume the garden has the shape shown below.
The length of fencing equals the distance around three sides of the rectangle plus that around the semicircle.
1. Around the rectangle
Distance = 28 ft + 14 ft + 28 ft = 70 ft
2. Around the semicircle
For a circle.
C = 2πr
For the semicircle,
½C =½(2πr) = πr
D = 14 ft, so
r = 7 ft
3. Total distance
Distance = 70 ft + 22 ft = 92 ft
Jordan will need 92 ft of fencing.
