Which of the following is the best definition of probability?
2 answers:
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Note that Range = Max – Min.
In this case, Max = 452452, Min = 221221.
Hence, Range = 452452 – 221221 = 228230.
Sample Variance:
where n = 4,
Hence
![s^2= \frac{1}{4-1}[( 419419 - 374374)^2 + (452452-374374)^2+\\ (404404-374374)^2+ (221221-374374)^2)]\\ = 1.0828 \times 10^{10} ](https://tex.z-dn.net/?f=%20s%5E2%3D%20%5Cfrac%7B1%7D%7B4-1%7D%5B%28%20419419%20-%20374374%29%5E2%20%2B%20%28452452-374374%29%5E2%2B%5C%5C%0A%28404404-374374%29%5E2%2B%20%28221221-374374%29%5E2%29%5D%5C%5C%0A%3D%201.0828%20%5Ctimes%2010%5E%7B10%7D%0A)
Then standard deviation =
In this case, Max = 452452, Min = 221221.
Hence, Range = 452452 – 221221 = 228230.
Sample Variance:
where n = 4,
Hence
Then standard deviation =
Answer:
<NPM + <NZM = 146°
Step-by-step explanation:
Given:
In triangle STU: M, N and P are the midpoints of the line TU, US and ST respectively.
Line UZ is the altitude of the triangle STU
<TSU =71°, <TSU = 36°, <TUS = 73°
From the diagram:
N is the midpoint of line SU and M is the mid point of line UT.
∴ Line NM is parallel to line ST
P is the mid point of line ST and M is the mid point of line UT
∴Line PM is parallel to line SU
N is the mid point of line SU and P is the mid point of line ST
∴Line NP is parallel to line UT
Δ SPN = Δ STU = 36°
<SPN + <NPM + <MPT (Sum of angles in a triangle = 180°)
<UST = <MPT = 71°
36° + <NPM + 71° = 180°
<NPM + 107° = 180°
<NPM= 180°-107°
<NPM= 73°
In ΔSNZ, line SN = line NZ
∴ side SN = side NZ
< NSZ = <NZS = 71°
<MTZ = <MZT = 36°
<NZS + <NZM <MZT = 180° (Sum of angles in a triangle = 180°)
71° + <NZM + 36° = 180°
107° + <NZM = 180°
<NZM = 180° - 107°
<NZM = 73°
<NPM + <NZM =73° + 73°
<NPM + <NZM = 146°
