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Aloiza [94]
3 years ago
12

Elements such as nitrogen,carbon,and oxygen cannot be made or destroyed they can only change their location by cycling through t

he biosphere true or false ??
Biology
2 answers:
Verizon [17]3 years ago
8 0

Answer:

true

Explanation:

marshall27 [118]3 years ago
3 0

Answer:

True

Explanation:

Chemicals like Nitrogen, Carbon and Oxygen cannot be made or destroyed they can only change their phase and location.

There are several biogeochemical cycle in the environment which keeps the essential nutrient in rotation within the ecosystem.

Such as carbon cycle, nitrogen cycle, phosphorus cycle etc.  

In all these cycles, the nutrient is being continuously cycled between the producer (plants & trees), consumers (animals & human beings) and the decomposers (bacteria’s etc.)  

These nutrients continuously changes their form and place in order to be in a used efficiently.

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strojnjashka [21]
The anser is C. recessive located on the X chromosome.
7 0
3 years ago
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Can we create effective vaccines or immunizations for lab made viruses? Or is it not possible because of the synthetic/man-made
Rashid [163]

Yes, it is possible to develop effective vaccines for any type of viruses. Genetically engineered viruses exhibit similar characteristics to natural viruses.

<h3>What is a virus?</h3>

A virus is a genetically independent entity that needs a suitable host to reproduce its genetic material (either DNA or RNA).

A genetically engineered virus is a virus whose genetic material has been modified using genetic engineering techniques.

Vaccines can be developed for removing any type of viruses because they take advantage of the intrinsic properties of the immune system (i.e., antigen recognition), independently of its origin.

Learn more about viruses here:

brainly.com/question/25236237

6 0
2 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
3 years ago
PLZZZ HELPPP<br> Explain how rocks can be analyzed to determine the history of an area.
larisa [96]

Answer:

Well let's take Sedimentary rock for example, The Law of Superposition which measures the average age of Sedimentary rocks using rocks around it. So you would use that rocks below it are older and that Extrusions and Intrusions are younger than the rocks which are stable.

Explanation: Hope it Helps With Your Work!

6 0
3 years ago
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Alona [7]

Natural selection is where positive traits survive more, allowing those to become more common. Mutation is where radioactivity changes genes in a random way. Natural selection allows positive mutation to become more common. Adaptation is where natural selection works for a species specifically more a new habitat.

5 0
3 years ago
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