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LiRa [457]
4 years ago
5

WILL MARK BRAINLIEST!!! NO NEED TO RUSH!!! What is an ecologist and a biochemist?

Biology
2 answers:
vekshin14 years ago
8 0

Ecology is largely observational, is concerned with interactions between living organisms in their natural habitats, and is carried out in the field. By contrast, biochemistry is experimental, is concerned with interactions at the molecular level, and is carried out at the laboratory bench.

hope this helps  you

jeyben [28]4 years ago
7 0

Ecology is largely observational, is concerned with interactions between living organisms in their natural habitats, and is carried out in the field. By contrast, biochemistry is experimental, is concerned with interactions at the molecular level, and is carried out at the laboratory bench.

and just put a person that

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When you breathe onto a cold window and water droplets appear, it is an example of
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An interaction between two organisms in which one usually benefits is known as .
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commercialism

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an association between two organisms in which one benefits and the other derives neither benefit nor harm.

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What is one possible result of an ovary not performing its intended function in the body?
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3 years ago
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We are studying 3 strains of bacteria, with populations p1, p2, p3, in an environment with three food sources, A, B, C. In a day
Nastasia [14]

Answer:

The population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.

Explanation:

From the given information:

For  food source A; we have:

3P₁ + P₂ + 2P₃ = 58    units of food A ---- (1)

For food source B; we have:

2P₁ + 4P₂ + 2P₃ = 70   units of food B  ---- (2)

For food source C; we have:

P₁ + P₂  = 20   units of food C    ----- (3)

From equation (1) and (2); we have:

3P₁ + P₂ + 2P₃ = 58

2P₁ + 4P₂ + 2P₃ = 70

By elimination method

 3P₁ + P₂ + 2P₃ = 58

-

 2P₁ + 4P₂ + 2P₃ = 70

<u>                                       </u>

<u> P₁  -   3P₂   + 0    = - 12    </u>

P₁ = -12 + 3P₂   ---- (4)

Replace, the value of P₁  in (4) into equation (3)

P₁ + P₂  = 20

-12 + 3P₂ + P₂  = 20

4P₂ = 20 + 12

4P₂ = 32

P₂ = 32/4

P₂ = 8

From equation (3) again;

P₁ + P₂  = 20

P₁ + 8 = 20

P₁  = 20 - 8

P₁  = 12

To find P₃;  replace the value of P₁ and P₂ into (1)

3P₁ + P₂ + 2P₃ = 58

3(12) + 8 + 2P₃ = 58

36 + 8 + 2P₃ = 58

2P₃ = 58 - 36 -8

2P₃ = 14

P₃ = 14/2

P₃ =  7

Thus, the population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.

4 0
3 years ago
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