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g100num [7]
3 years ago
7

Find the surface area of the come in terms of pi.

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
5 0

Answer: first option

Step-by-step explanation:

 The formula for calculate the surface area of a cone is the shown below:

SA=rs\pi+r^{2}\pi

Where: s is the slant height and r is the radius.

As you can see in the figure the slant height and the radius are:

 s=18 cm and r=6 cm

Therefore when you substitute the values shown above into the formula, you obtain that the result is:

SA=(6cm)(18cm)\pi+(6cm)^{2}\pi=144\picm²

Monica [59]3 years ago
5 0

Answer:

144\pi  sq. cm.

Step-by-step explanation:

Surface Area of cone is given by the formula  \pi r^2+\pi rl

The diameter is given as 12, hence radius (r) is half of that, 6.

The slant height (l) is given as 18

<em>Plugging all the values into the formula, we get:</em>

\pi r^2 + \pi r l\\=\pi(6)^2+\pi (6)(18)\\=36\pi +108 \pi\\=144\pi

First answer choice is right,  144\pi sq. cm.

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
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Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
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