Find the coordinates of C' after a reflection across the line
1 answer:
<h3>Answer: (4,2)</h3>
==============================================================
Explanation:
C is at (0,0). Ignore the other points.
Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.
Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"
So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.
All of this is shown in the diagram below.
You might be interested in
Answer:
Factors:
Step-by-step explanation:
We are given a polynomial:
We have to factor the given polynomial into its complex factors.
The factorization can be done as follows:
The general formula for exponential growth and decays is:
if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.
Now we need to classify each of the functions:
1.
The function
can be wrtten as:
comparing with the general formula we notice that k=2, therefore this is an exponential growth.
2.
The function
can be written as:
comparing with the general formula we notice that k=-4, therefore this is an exponential decay.
3.
The function
comparing with the general formula we notice that k=-1, therefore this is an exponential decay.