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3 years ago

I need help again help me pllsssssss

Mathematics

2 answers:

notka56 [123]3 years ago

8 0

Answer: you end up at (2,2)

Step-by-step explanation:

daser333 [38]3 years ago

3 0

Answer:

2,2

Step-by-step explanation:

go down to the bottom right corner (5,-5)

move over left 3 boxes

and then up 7 boxes

hope this helps :P

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Last week, Evelyn ran 44 laps at the community center. Peter ran 75% of the number of laps that Evelyn ran. How many laps did Pe

emmainna [20.7K]

Answer:

Peter ran 33 laps.

Step-by-step explanation:

Multiply Evelyn's 44 laps by 75% or 0.75 to get your answer.

44(0.75)=33

3 0

3 years ago

W Circumference (definition)

natita [175]

Answer:

Definition: The enclosing boundary of a curved geometric figure, especially a circle.

Step-by-step explanation:

8 0

3 years ago

A pill has the shape of a cylinder with a hemisphere at each end. The height of the cylindrical portion is 12mm and the overall

Volgvan

Answer:

The volume of the pill is $V=452\ mm^{3}$

Step-by-step explanation:

Find the volume of the pill in cubic millimeters

we know that

The volume of the pill is equal to the volume of the cylinder plus the volume of a sphere (two hemisphere is equal to one sphere)

we have

$V=\frac{4}{3}\pi r^{3}+\pi r^{2}h$

$r= (18-12)/2=3\ mm\\ h=12\ mm$

assume

$\pi =3.14$

substitute

$V=\frac{4}{3}(3.14)(3)^{3}+(3.14)(3)^{2}(12)\\V=452\ mm^{3}$

8 0

3 years ago

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

One number is 5 times another number.their sum is 90.find the numbers.

alexgriva [62]

Step-by-step explanation:

let both unknowns be x and y

x = 5y. ......(1)

x + y = 90. ......(2)

sub eqn (1) into eqn (2)

5y + y = 90

6y = 90

y = 90/6

= 15

sub y = 15 to eqn (1)

x = 5y

x = 5 × 15

× = 75

4 0

3 years ago