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Svetlanka [38]
3 years ago
12

_____ is a single trial or a group of trials

Mathematics
1 answer:
Illusion [34]3 years ago
7 0

Answer:

Kind of a guess bc there are lots of words that would work but how about "test"?

Step-by-step explanation:

You might be interested in
A company makes two calculator models, one designed specifically for financial use and the other designed for scientific use. Th
mihalych1998 [28]

Answer:

  • 280 financial
  • 20 scientific

Step-by-step explanation:

The linear programming problem can be formulated as ...

  minimize 10f +12s    subject to ...

  10f +20s ≥ 3200 . . . . number of chips used

  f + s ≥ 300 . . . . . . . . . .number of switches used

  f ≥ 100 . . . . . . . . . . . . .minimum number of financial calculators

Graphing these inequalities, we find the feasible region to be bounded by the points (f, s) = (100, 200), (280, 20), (320, 0). The one of these that minimizes the number of production steps is ...

  f = 280, s = 20

280 financial and 20 scientific calculators should be produced to minimize the number of production steps.

4 0
4 years ago
Are negative fractions always to the right of zero?
Tasya [4]

Answer:

no because negatives are to the left and positives are to the right

6 0
3 years ago
The cancellation property sin−1(sin(x)) = x is valid for x in what interval
pochemuha

Answer:

It is given that : Sin^{-1}(Sin (x) =x

As we have to find the Domain of Sin^{-1}(Sin (x).

-1 ≤ sin x ≤1

Sin^{-1}(-1)\leq Sin^{-1}(Sin x)\leq Sin^{-1}(1)\\\frac{-\pi}{2}\leq x\leq \frac{\pi }{2}

So it is defined for x lying between (\frac{-\pi}{2}, \frac{\pi }{2}) .

As meaning of Domain is those values of x for which any function f(x) is defined.

4 0
3 years ago
Factor out the GCF of the three terms, then complete the factorization of 6x3 + 6x2 – 1202.
Fittoniya [83]

Answer : 2( 3x^3 +3x^2 - 601 )

3 0
3 years ago
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 8x and y = 2x + 2 intersect are the so
son4ous [18]

Answer:

(A)

As per the given condition.

You have 2 equations for y.

i,e y =8x and y= 2x+2

then, they will intersect at some point where y is the same for both equations.

That is why in equation y=8x you exchange y with other equation you got which is y=2x+2 once you do this you will have

8x = 2x+2  and the solution of which will satisfy both equation.

(B)

8x = 2x + 2

to find the solutions take the integer values of x between -3 and 3.

x = -3 , then

8(-3) = 2(-3) +2

-24 = -6+2

-12 = -4    False.

similarly, for x = -2

8(-2) = 2(-2)+2

-16 = -2   False

x = -1

8(-1) = 2(-1)+2

-8= 0   False

x = 0

8(0) = 2(0)+2

0= 2   False

x = 1

8(1) = 2(1)+2

8= 4   False

x = 2

8(2) = 2(2)+2

16 = 6   False

x = 3

8(3) = 2(3)+2

24 = 8   False

there is no solution to 8x = 2x +2 for the integers values of x between -3 and 3.

(C)

The equations cab be solved graphically by plotting the two given functions on a coordinate plane and identifying the point of intersection of the two graphs.

The point of intersection are the values of the variables which satisfy both equations at a particular point.

you can see the graph as shown below , the point of intersection at x =0.333 and value of y = 2.667









3 0
3 years ago
Read 2 more answers
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