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GenaCL600 [577]
4 years ago
12

What is the solution to the equation:

Mathematics
1 answer:
Setler [38]4 years ago
7 0
The solution to the equation is “ x = -4”.
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You record the temperature for 12 days The data is shown in the table which number describe how all values in the data set vary
ArbitrLikvidat [17]

Answer:

A) 11

Step-by-step explanation:

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4 years ago
What is the sum of 7x/(x^2-4) and 2/(x+2)​
ioda

Answer:

The answer is 9x-4/(x+2)(x-2)

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Solve pls brainliest
zepelin [54]

Answer:

(1,6)

Step-by-step explanation:

all u gotta do is look at the graph, the school is at x=1 and y=6 so therefore (1,6)

5 0
3 years ago
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(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

7 0
3 years ago
Please help iam crying this is my final exam please
sertanlavr [38]

Given:

The graph of a system of equations.

To find:

The solution of the given system of equations.

Solution:

If a system of equations has two equations, then the intersection points of the graphs of these two equations are the solutions for the system of equations.

From the given graph it is clear that the graph of both line intersect each other at point (-0.5,0.5).

Therefore, the solution is (-0.5,0.5).

5 0
3 years ago
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