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mina [271]
3 years ago
15

Brandon rolls a six sided die twenty times, and records the result in the table below. How many times did Brandon roll above the

average?
a. 14
b. 7
c. 5
d. 4

Mathematics
2 answers:
atroni [7]3 years ago
8 0

The answer is b on Edge.

If you look for the mode within the data table, you will find that the number 4 shows up the most. So, just count any number 5's or 6's that you see and you should be able to determine that he rolled above the average a total of 7 times.

Svet_ta [14]3 years ago
3 0
D
all you need to do is add up all the numbers then divide it by the total of rolls he did. which was 20.
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Can someone solve this
77julia77 [94]

Answer:

A ≈ 269.81 cm²

Step-by-step explanation:

This shape is a hexagon (it has 6 sides) so let's use the formula for the area of a hexagon.

A = \frac{3\sqrt{3} }{2} s^{2}

Where s is the length of the sides

Substitute:

A = \frac{3\sqrt{3} }{2} s^{2}

A = \frac{3\sqrt{3} }{2} 10^{2}

Solve:

A = \frac{3\sqrt{3} }{2} 10^{2}

A = \frac{3\sqrt{3} }{2} 100

Multiply the numerator:

A = \frac{3\sqrt{3} }{2} 100

A ≈ \frac{5.12 }{2} 100

(The numerator reflects a rounded number, but the actual calculations are exact)

Divide the fraction:

A ≈ \frac{5.12 }{2} 100

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Multiply:

A ≈ 2.6(100)

A ≈ 269.81 cm²

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6 0
3 years ago
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Makovka662 [10]

Answer:

The maximum height is reached after 3.75 seconds.

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... (120 ft/s)/(32 ft/s²) = t = 3.75 s

The ball will not go any higher after its vertical speed is zero.

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