Integrate <span>f ''(x) = −2 + 36x − 12x2 with respect to x:
f '(x) = -2x + (36/2)x^2 - (12/3)x^3 + c. Find c by letting x = 0 and using f(0)=8.
Then f '(0) = -2x + 18x^2 - 4x^3 + c = 18 (which was given).
Then -0 + 0 - 0 + c = 18, so c = 18 and
f '(x) = </span>-2x + 18x^2 - 4x^3 + 18.
Go through the same integration process to find f(x).
Answer:
ok loll
Step-by-step explanation:
Answer:
(y-(-2))/(x-(-1)= (-2-4)/(-1-3)
(y+2)/(x+1)= (-6)/(-4)
(y+2)/(x+1)= (3/2)
Cross multiplying
2y+4= 3x+3
3x-2y-1=0
The angle x is half the sum of the intercepted arcs, PQ and NO.
... (1/2)(65° + 45°) = 55° = x° = m∠PMQ
