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3 years ago

What is the probability that a number selected at random from the set {2,3,7,12,15,22,72,108} will be divisible by both 2 and 3?

1 answer:

5 0

Answer: 3/8
There are only three numbers in there that 2 and 3 can go into evenly.

The probability that you will randomly select one of those numbers is 3/8.

-Brainly Answerer

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What is the value of s

frutty [35]

Answer:

30.9°

Step-by-step explanation:

Right Angle Triangle = 90°

59.1 + ? = 90

90 - 59.1 = 30.9

7 0

3 years ago

Read 2 more answers

Probability. CORRECT answer gets brainliest.

Dima020 [189]

The probability of spinning on yellow would be 1/3 because this is broken into 3 pieces and that would be the probability of something that has been broken into 3 pieces, and 1/3 in decimal form would be 0.33.

The probability of spinning a blue would be 1/2 because the blue is broken into 1/2 of the spinner, therefore the probability of spinning a blue would be 1/2, and 1/2 in decimal form would be 0.5.

Therefore your answers are,

Blue=0.5

Yellow=0.33

3 0

3 years ago

Please help very urgent

Alik [6]

Answer:

32, 16, 8, 4, 2, 1

Explanation:

The geometric mean can be represented by $\sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}$ .

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

$a_{n} = a_{1} • r^{n-1}$

Where $a_{n}$ is the nth term, $a_{1}$ is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, $a_{1}$ will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

$\sqrt[5]{\frac{a_{6}}{a_{1}}}$ =

$\sqrt[5]{\frac{1}{32}}$ =

$\frac{1}{2}$ .

Therefore: $r = \frac{1}{2}$ .

Using all the information we have, we can find the explicit rule:

$a_{n} = a_{1} • r^{n-1}$

$a_{1}$ = 32
$r = \frac{1}{2}$

$a_{n} = a_{1} • r^{n-1}$ →

$\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}$

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

$a_{1} = 32 • (\frac{1}{2})^{1-1}$

$a_{1} = 32 • (\frac{1}{2})^{0}$

$a_{1} = 32 • 1$

$a_{1} = 32$

$a_{6} = 32 • (\frac{1}{2})^{6-1}$

$a_{6} = 32 • (\frac{1}{2})^{5}$

$a_{6} = 32 • \frac{1}{32}$

$a_{6} = 1$

3 0

3 years ago

Read 2 more answers

Does anyone get this?

stepladder [879]

Answer: B

Step-by-step explanation:

In the systems of equation it already gives you the solution for x which is -2 so all you have to do is substitute -2 into the first equation and solve for y.

y= 2/3x + 3

x= -2

Substitute x for -2

y = $\frac{2}{3}* \frac{-2}1} + 3$