Answer is D :)
hope it helps
Let's call L the width of the rectangle and W its width. The area of the rectangle is the product between the length and the width, and we are also told that the area is 300 square meters, so we can write

Moreover, we know that the length is 5 meters longer than the width:

We have a system of 2 equations in 2 unknown variables, L and W. If we substitute the second equation into the first one, we get


which has two solutions: W=-20 and W=15. We can discard the negative solution since it does not have physical meaning, and now we can substitute the value of W into the second equation to find L:

<span>Therefore, the rectangle has width 15 meters and length 20 meters.</span>
First we need to figure out how long YK is and the best way to do this is to set up a proportion
34 x
----- = ------
95.2 168
then cross multiply and divide
34 times 168=5712/95.2=60
then add the two parts of the line
60+34=94
X is 94 cm
I hope I've helped!