One hundred sixty divided by one fourth equals what

olga nikolaevna [1]

to prove that 6720. Sin 40. Sin 60. 80 equals 3 you'd have to divide 16 by 20 multiply subtract both sides by 3 which is 24x + 6x + 8x + -14 equals 40 40 + 20 equals 16 - -40 equals 80 which equals to 3

6 0

4 years ago

Joyce is training for a race the ratio of the number of minutes she runs to the number of miles she wants is 24 to 3 she plans t

CaHeK987 [17]

Answer:

84

Step-by-step explanation:

6 0

3 years ago

The CEO of a clothing company estimates that 52% of customers will make a purchase. Part A: How many customers should a salesper

4vir4ik [10]

Answer:

(a) The expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b) The probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

Step-by-step explanation:

Let the random variable X be defined as the number of customers the salesperson assists before a customer makes a purchase.

The probability that a customer makes a purchase is, p = 0.52.

The random variable X follows a Geometric distribution since it describes the distribution of the number of trials before the first success.

The probability mass function of X is:

$P(X=x)=(1-p)^{x}p$

The expected value of a Geometric distribution is:

$E(X)=\frac{1-p}{p}$

(a)

Compute the expected number of should a salesperson expect until she finds a customer that makes a purchase as follows:

$E(X)=\frac{1-p}{p}$

$=\frac{1-0.52}{0.52}\\=0.9231$

This, the expected number of should a salesperson expect until she finds a customer that makes a purchase is 0.9231.

(b)

Compute the probability that a salesperson helps 3 customers until she finds the first person to make a purchase as follows:

$P(X=3)=(1-0.52)^{3}\times0.52\\=0.110592\times 0.52\\=0.05750784\\\approx 0.058$

Thus, the probability that a salesperson helps 3 customers until she finds the first person to make a purchase is 0.058.

8 0

3 years ago

One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.

vampirchik [111]

◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie

5 0

3 years ago

Work out the lengh of RS gue your answer to 3 significant figures

atroni [7]

Answer:

RS ≈ 5.83 units

Step-by-step explanation:

Calculate RS using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = R(- 3, 1) and (x₂, y₂ ) = S(2, 4)

RS = $\sqrt{(2+3)^2+(4-1)^2}$