Answer:
Teo is 11 years old and Richard is 26 years old.
Step-by-step explanation:
Let R be the age of Richard and T be the age of Teo.
<u><em>First set up the equations:</em></u>
The combined age of Teo and Richard is 37:
R+T=37
Richard is four years old than twice Teo's age:
R=2T+4
<u><em>Then, solve the equations:</em></u>
Substitute (2) to (1) and solve for T:
(2T+4)+T=37
3T=11
T=11
Solve for R using (2):
R=2(11)+4
R=22+4
R=26
Answer:
The required inequality is: 12 ≤ 3x < 21
Step-by-step explanation:
We are given: three times a number is greater than or equal to 12 and less than 21
We need to answer following questions:
1) The inequality translated in numerical form
Let number = x
12 ≤ 3x < 21
2) Your work solving the inequality
We need to find value of x. Divide the inequality by x
4 ≤ x < 7
3) The solution graphed on a number line
It is shown in figure attached.
4) The solution in set notation
The set notation is: Considering x belongs to natural numbers N
{∀ x|x∈N, 4 ≤ x < 7}
5) The solution in interval notation
The interval notation is: [4,7)
because we have 4 less than equal to x and x is less than 7
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.



Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
Answer:
x =2 x = -1
Step-by-step explanation:
|2x - 1| + 3 = 6.
Subtract 3 from each side
|2x - 1| + 3-3 = 6-3
|2x - 1|= 3
An absolute value has two solutions, one positive and one negative
2x-1 =3 2x -1 = -3
Add 1 to all sides
2x-1+1 =3+1 2x-1+1 = -3+1
2x = 4 2x =-2
Divide by 2
2x/2 = 4/2 2x/2 = -2/2
x =2 x = -1