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RUDIKE [14]
3 years ago
5

A scuba diver descends 63 feet in 18 seconds.

Mathematics
1 answer:
Elanso [62]3 years ago
5 0

Answer:

3.5

Step-by-step explanation:

the answer is 3.5 because when you divide 63 and 18 you get 3.5

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Ray UW is the angle bisector of AngleVUT.
tester [92]

Answer:

AngleWUT =38°, option 2

Step-by-step explanation:

We have three rays passing through U. A ray is set extend in one direction with one fixed point.

We have UW ray bisecting VUT.As the ray bisects the angle between VUW and WUT would be same .

Given angles are (4x+6)° and (6x-10)°.

As these angles are equal

4x+6=6x-10

2x=16

x=8

AngleWUT = (6x – 10)°

and x is 8 so on substituting AngleWUT =38°.

5 0
3 years ago
Read 2 more answers
I tried multiplying it but I still can’t figure it out please please help
neonofarm [45]
The answer is 88 5/6 .   If you were stuck try turning the fractions into improper fractions and multiply both of them and later divide the numerator by the denominator to have a mixed number.  You can later simplify the fraction to get 88 5/6.  If you need help don't be afraid to tell me in the comments!   Hope this helps :)
3 0
3 years ago
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BARSIC [14]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Describe how to write 7,594,000,000 in scientific notation. Complete the description. First move the decimal point places to the
s2008m [1.1K]

Step-by-step explanation:

The given number is 7,594,000,000.

To convert it into scientific notation,

First move the decimal point places to the left to find a number that is greater than or equal to 1 and less than 10. Then multiply by 10 , using an exponent on 10 that equals the number of places you moved the decimal. The exponent is negative if the original no was <1 and the exponent is positive, if the original number was  > 1.

In 7,594,000,000, we move the decimal point places to the left before 5. It means we have moved 9 digits left.

Hence, 7,594,000,000=7.59\times 10^9 is the scientific notation.

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3 years ago
How many feet are traveled by a person riding once around the merry -go-round ? Clare says, " The radius of the merry -go-round
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