Find the vertex: -4x^2 + 16x - 7
Vertex = ( x, f(x)).
x = -b/2a
x = -16/2(-4)
x = -16/-8
x = 2
f(x) = -4x^2 + 16x - 7
Let x = 2
f(2) = -4(2)^2 + 16(2) - 7
f(2) = -4(4) + 32 - 7
f(2) = -16 + 32 - 7
f(2) = 16 - 7
f(2) = 9
Vertex = (2, 9)
The expression is (2x2)+5
Answer:
Solution By Gauss jordan elimination method
x = 3, y = 2 and z = 4
Answer:
(0,-2), (5,0) and (10,2).
Step-by-step explanation:
Given equation is
.
Now we need to find 3 pairs of solutions in (x,y) form for the given equation.
As
is a linear equation so we are free to pick any number for x like x=0, 5, 10
Plug x=0 into
, we get:





Hence first solution is (0,-2)
We can repeat same process with x=5 and 10 to get the other solutions.
Hence final answer is (0,-2), (5,0) and (10,2).