Lake Mead contains approximately 28,945,000 acre feet of water and there are about 326,099 gallons in 1 acre-foot. The approxima
1 answer:
You might be interested in
Answer:
a) We have that the significance is given by and we know that we have a right tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.01,0,1)"
And we got for this case
So then the rejection region would be
b) We have that the significance is given by ,
and we know that we have a two tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.025,0,1)"
And we got for this case
So then the rejection region would be
Step-by-step explanation:
Part a
We have that the significance is given by and we know that we have a right tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.01,0,1)"
And we got for this case
So then the rejection region would be
Part b
We have that the significance is given by ,
and we know that we have a two tailed test.
So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:
"=NORM.INV(1-0.025,0,1)"
And we got for this case
So then the rejection region would be