Question

Lake Mead contains approximately 28,945,000 acre feet of water and there are about 326,099 gallons in 1 acre-foot. The approximate number of gallons of water in lake Mead is 9.4x10^a what is the value of a ?

Answer 1

Answer:

12

Step-by-step explanation:

Let x be the number of gallons of water in lake Mead.

Given that  there is 326099 gallons in 1 acre-foot, we calculate Mead's gallons as:

$1 acrefoot=326099g\\28945000acrefoot=x\\\\x=\frac{28945000acrefoot\times326099g}{1acrefoot}\\\\x=9.4\times 10^{12} \ gallons$

We now equate x to $9.4\times10^a$;

$9.4\times 10^a=9.4\times 10^{12}\\\\a=12$

Hence, a=12