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frez [133]
3 years ago
7

Consider the system of equations.

Mathematics
2 answers:
frosja888 [35]3 years ago
6 0

Answer:

First part: -10x-4y=-12

Second half: infinitely many solutions

Step-by-step explanation:

Just did the assignment and got it correct

Sholpan [36]3 years ago
3 0

Answer:

Part 1. -10x - 4y = -12

Step-by-step explanation:

Part 2. Infinitely Many Solutions

Got it correct on Edge 2020

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Solve the system of linear equations by substitution 12x+y=−4 y=2x+16
ki77a [65]

Answer:

Your solution is (-10/7, 92/7)

Step-by-step explanation:

12x + y = -4

y = 2x + 16

To use substitution, we want to plug one variable's equation into the other equation.

We can see that y is already solved for us. Plug y into the first equation.

12x + y = -4

12x + (2x + 16) = -4

Combine like terms.

14x + 16 = -4

Subtract 16 from both sides.

14x = -20

Divide both sides by 14.

x = -20/14

x = -10/7

Now that we know x, we will plug it into one of the other equations.

y = 2x + 16

y = 2(-10/7) + 16

Multiply.

y = -20/7 + 16

Add.

y = -20/7 + 112/7

y = 92/7

Your solution is (-10/7, 92/7)

Hope this helps!

8 0
3 years ago
jery mixes the lrters F.P.M.M.M.F.P. and J thoroughly. With ouy looking Amanda draws one leter . Expressed as a fraction,decimal
Tanzania [10]

Answer:

3.45

Step-by-step explanation:

3 0
3 years ago
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mario62 [17]
I think a is your answer
7 0
3 years ago
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On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3)
goldfiish [28.3K]

Answer:

f(x) > 0 over the interval (-\infty,-4)

Step-by-step explanation:

If  f(x)  is a continuous function,  and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.

Then the function was above the x axis (larger than zero) from - \infty, until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.

There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from - \infty to -3, since between the  values -4 and -3 the function adopts negative values.

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3 years ago
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-9+m=13 for equations
Nataly_w [17]

Answer:

m=22

Step-by-step explanation:

i am very very shmart

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