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3 years ago

Isaac is 3 years older than Rachael. In 4 years the sum of their ages will be 75. How old is Isaac now?

Mathematics

2 answers:

MatroZZZ [7]3 years ago

6 0

Answer:

36 years old

Step-by-step explanation:

let x = age of Rachael

2x+3 = current ages combined

[(2x+3)+4]+4 = 75

2x+11 = 75

2x = 75-11

2x = 64

x = 32

Rachel is 32 years old. Isaac is 3 years older, which is 35 years old.

Hope this helped! If you need any help, tell me in the comments.

IRINA_888 [86]3 years ago

4 0

I hope this clears it up. R is Rachaels age and I is Isaacs age. The first equation at the top represents that Isaac is 3 years older than Rachael. The second equation represents their combined ages in 4 years. Follow the arrows to see where I get my numbers and variables

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alexira [117]

Answer:

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Step-by-step explanation:

Here the parent function is f(x)=log x. The function has y intercept as 0 at x=1 .

If we observe the translated function we will observe that , the y intercept of new function is 0 at x=-3. Hence the function is moving ahead of the parent function by 4 units and reaches the y intercept being 0.

If we graph

g(X)= log X

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vlabodo [156]

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3 years ago

Maya had $27. She spent all the money on buying 3 burgers for $x each and 2 sandwiches for $y each. If Maya would have bought 2

defon

Answer:

Option C

The student's conclusion is correct because the solution to the system of equations $3x+2y=27$ and $2x+y=16$ is $(5,6)$

Step-by-step explanation:

Let

x------> the cost of each burger

y-----> the cost of each sandwich

we know that

$3x+2y=27$ -----> equation A

$2x+y=(27-11)$

$2x+y=16$ ----> equation B

Solve the system of equations

Multiply the equation B by $-2$

$-2(2x+y)=-2*16$ -----> $-4x-2y=-32$ ------> equation C

Adds equation A and equation C

$3x+2y=27 \\-4x-2y=-32\\ ----------\\ 3x-4x=27-32\\ -x=-5\\x=5$

Substitute the value of x in the equation B

$2(5)+y=16$

$10+y=16$

$y=6$

The solution of the system of equations is the point $(5,6)$

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kaheart [24]

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Answer:
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Aloiza [94]

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