Answer:
50π cm²
Step-by-step explanation:
In this case we have that the area of the boomerang has been the area of the largest semicircle minus the area of the smaller semicircles.
We know that the radius is half the diameter:
r = d / 2 = 20/2
r = 10
Now we have to:
Alargest = π · r²
Alargest = π · (10 cm) ²
Alargest = 100π cm²
Asmaller = π · r²
Asmaller = π · (5 cm) ²
Asmaller = 25π cm²
Finally, the boomerang area has been:
Aboomerang = 100π cm² - 2 · (25π cm²)
Aboomerang = 50π cm²
Answer:
by my degree in math and other things this is correct.
If the entire ray is PQ, then all of those points lie on the ray.
Area of AAFD= 54centimeters squared
Answer:
5 zeros maximum
Step-by-step explanation:
Recall that a polynomial has as many roots (zeros) in the Complex number system, as its degree. So in the given case, where the leading term of the polynomial carries order 5, the maximum number of zeros for the given function cannot be larger than 5.
