Answer:
First brand of antifreeze: 21 gallons
Second brand of antifreeze: 9 gallons
Step-by-step explanation:
Let's call A the amount of first brand of antifreeze. 20% pure antifreeze
Let's call B the amount of second brand of antifreeze. 70% pure antifreeze
The resulting mixture should have 35% pure antifreeze, and 30 gallons.
Then we know that the total amount of mixture will be:

Then the total amount of pure antifreeze in the mixture will be:


Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -0.7 and add it to the second equation:



+

--------------------------------------



We substitute the value of A into one of the two equations and solve for B.


Answer:
I would go with C.Line 4
Please mark brainliest!
Step-by-step explanation:
The answer is B, because all 4 sides should be equal on a rhombus.
Regroup terms:
y - 2/9 ≤ 5/9
Add 2/9 to both sides:
y ≤ 5/9 + 2/9
Simplify 5/9 + 2/9 to 7/9:
y ≤ 7/9