Answer:
The most reasonable is 2 h
Step-by-step explanation:
If you see the graph is decreasing in hours while is increasing in years. When a person is 45 years the amount of daily physical activity is 3 hours, so a person that is 50 years needs to do less than 3 hours a day and the only option less than 3 hours is 2 hours.
The interquartile range of the data set is 18, hope this helps :)
.361 .36 .35 1/5
1/5 = .20
Answer:
![2 < y < 12](https://tex.z-dn.net/?f=2%20%3C%20y%20%3C%2012)
Step-by-step explanation:
Given
![x = 7](https://tex.z-dn.net/?f=x%20%3D%207)
![z = 5](https://tex.z-dn.net/?f=z%20%3D%205)
Required
What must be true about y?
To answer this, we first calculate the range as follows;
![Minimum = |x - z|](https://tex.z-dn.net/?f=Minimum%20%3D%20%7Cx%20-%20z%7C)
and
![Maximum = |x + z|](https://tex.z-dn.net/?f=Maximum%20%3D%20%7Cx%20%2B%20z%7C)
For Minimum, we have:
![Minimum = |7 - 5|](https://tex.z-dn.net/?f=Minimum%20%3D%20%7C7%20-%205%7C)
![Minimum = |2|](https://tex.z-dn.net/?f=Minimum%20%3D%20%7C2%7C)
![Minimum = 2](https://tex.z-dn.net/?f=Minimum%20%3D%202)
For Maximum, we have:
![Maximum = |7 + 5|](https://tex.z-dn.net/?f=Maximum%20%3D%20%7C7%20%2B%205%7C)
![Maximum = |12|](https://tex.z-dn.net/?f=Maximum%20%3D%20%7C12%7C)
![Maximum = 12](https://tex.z-dn.net/?f=Maximum%20%3D%2012)
The values of y are then bounded by the following:
![Minimum < y < Maximum](https://tex.z-dn.net/?f=Minimum%20%3C%20y%20%3C%20Maximum)
This gives
![2 < y < 12](https://tex.z-dn.net/?f=2%20%3C%20y%20%3C%2012)