Question

Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form

Answer 1

Answer:

Final answer is $x-6y=23$

Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

So first we need to find the slope of given line.

rewirite x=6y-5 in y=mx+b form

x+5=6y

$\frac{1}{6}x+\frac{5}{6}=y$

Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

$y-y_1=m\left(x-x_1\right)$

$y-(-3)=\frac{1}{6}\left(x-5\right)$

$y+3=\frac{1}{6}x-\frac{5}{6}$

$y=\frac{1}{6}x-\frac{5}{6}-3$

$y=\frac{1}{6}x-\frac{23}{6}$

Now we need to rewrite that equation in standard form. Ax+By=C.

6y=x-23

x-23=6y

x-6y=23

Hence final answer is $x-6y=23$