Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
iangle CBD△ABD≅△CBD.
1 answer:
Answer:
The Proof for
△ABD ≅ △CBD is below
Step-by-step explanation:
Given:
AD = CD .........BD bisect AC
To Prove:
△ABD ≅ △CBD
Proof:
In ΔABD and ΔCBD
BD ≅ BD ....……….{Reflexive Property}
∠ADB ≅ ∠CDB …………..{Measure of each angle is 90°( )}
AD ≅ CD ....……….{ }
ΔABD ≅ ΔCBD .......….{By Side-Angle-Side Congruence test} ...Proved
You might be interested in
Answer:
The inner function is and the outer function is
.
The derivative of the function is .
Step-by-step explanation:
A composite function can be written as , where
and
are basic functions.
For the function .
The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.
Here, we have inside parentheses. So
is the inner function and the outer function is
.
The chain rule says:
It tells us how to differentiate composite functions.
The function is the composition,
, of
outside function:
inside function:
The derivative of this is computed as
The derivative of the function is .