33000 dollars was invested. part at 4% and part at 7%. for the period of one year. the annual interest was 1950 dollars. how muc
h was invested at each rate?
1 answer:
Inv1 investment 1
inv2 investment 2
A) inv1 + inv2 = 33,000
B) .04 inv1 + .07 inv2 = 1,950
Multiplying A) by -.04
A) -.04 inv1 - .04 inv2 = -1,320
Then adding B)
B) .04 inv1 + .07 inv2 = 1,950
.03 inv2 = 630
inv2 = 630 / .03
inv2 = 21,000 invested at 7%
inv1 = 33,000 -21,000=
12,000 invested at 4%
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<span>1. Find the difference
2. Divide the difference by the original number it went up from.
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