Question

The temperature of a piece of Metal X with a mass of 95.4g increases from 25.0°C to 48.0°C as the metal absorbs 849 J of heat. What is the specific heat of Metal X?

Answer 1

Answer:

c = 0.38 J/g °C

Step-by-step explanation:

We have,

Mass of metal X is 95.4 g

Initial temperature was 25°C and final temperature is 48°C.

The metal absorbs 849 J of heat

The heat absorbed due to change in temperature is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{849}{95.4\times (48-25)}\\\\c= 0.38\ J/g^{\circ} C$

So, the specific heat of metal X is 0.38 J/g °C.