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kifflom [539]
3 years ago
12

Is there a solution y=3x+1 y=3x+5

Mathematics
2 answers:
Bogdan [553]3 years ago
4 0

Answer:

y = 3 x + 1

y = 3 x + 5

(no solutions exist)

Step-by-step explanation:

umka21 [38]3 years ago
3 0

Answer:y = 3x + 5 is a linear equation in two variables and it has infinite possible solutions.

Step-by-step explanation:

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What Is The Answer For -6( -2+a ) = 54
WITCHER [35]

Answer:

a = (-7)

Step-by-step explanation:

Firstly clear the bracket...,

-6(-2 + a) = 12 - 6a

Then substitute the simplified version in place of bracket...,

; 12 - 6a = 54

; -6a = 54 - 12

; -6a = 42...then divide both sides by (-6)

Therefore...., a = (-7)

3 0
2 years ago
What is the fourth number in this pattern, and what is the rule?
Ainat [17]

Answer: Multiplied by 10

Step-by-step explanation:

3 0
3 years ago
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Please help as soon as possible I really need help rn I don’t get this at all
Rudiy27
G=0 would be your answer as it is greater than the number
5 0
3 years ago
Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an
Natasha_Volkova [10]

Answer:

The volume of the solid is 243\sqrt{2} \ \pi

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0  ≤ ρ²   ≤   81

0  ≤ ρ   ≤  9

The intersection that takes place in the sphere and the cone is:

x^2 +y^2 ( \sqrt{x^2 +y^2 })^2  = 81

2(x^2 + y^2) =81

x^2 +y^2 = \dfrac{81}{2}

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

z = \sqrt{x^2+y^2}

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; \dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}

Thus, volume: V  = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4}  \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho   ^2 \ sin \phi \ d\rho \   d \theta \  d \phi

V  = \int \limits^{\pi/2}_{\pi/4} \ sin \phi  \ d \phi  \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho   ^2 d\rho

V = \bigg [-cos \phi  \bigg]^{\pi/2}_{\pi/4}  \bigg [\theta  \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3}  \bigg ]^{9}_{0}

V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]

V = 243\sqrt{2} \ \pi

4 0
3 years ago
PLS HELP WILL MARK YOU BRAINLIEST! NO FAKE ANSWERS
bixtya [17]

Answer:

30%

Step-by-step explanation:

the first solution -30% will be 45% and the second solution added by 30% will be 45%

4 0
2 years ago
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