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polet [3.4K]
4 years ago
5

demochares has ived a fourth of his life as a boy, a fifth as a youth, a third as a man, and has spend 13 years in his dotage. h

ow old is he?
Mathematics
1 answer:
kifflom [539]4 years ago
8 0

Answer:  60 years

Step-by-step explanation:

Let x denotes the age of Demochares .

Time he spent as a boy = \dfrac{x}{4}

Time he spent as a youth = \dfrac{x}{5}

Time he spent as a man= \dfrac{x}{3}

Time he spent in dotage= 13 years

As per given , we have the following equation:

x=\dfrac{x}{4}+\dfrac{x}{5}+\dfrac{x}{3}+13

x=\dfrac{15x+12x+20x}{60}+13  [Take LCM]

x=\dfrac{47x}{60}+13

x-\dfrac{47x}{60}=13

\dfrac{60x-47x}{60}=13

\dfrac{13x}{60}=13

x=13\times\dfrac{60}{13}=60

Hence, he is 60 years old.

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What is the proportional relationship show in 8 tablespoons of honey for every 10 cups of flour.
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Answer:

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Step-by-step explanation:

8 : 10

4 : 5

hope this was helpful : )

6 0
3 years ago
If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)
\\\\\\
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\\\\\\
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\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
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now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

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Hello from MrBillDoesMath!

Answer:    360


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36 * 10 = 360

 

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8 0
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