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Ksju [112]
3 years ago
10

What is the value of b^2-4ac for the following equation 2x^2-2x-1=0

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0
Here a = 2, b = -2, c = -1
b^2-4ac = (-2)^2 - 4(2)(-1)
= 4 +8
= 12
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Answer:

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the axis of symmetry of a quadratic equation is x = –3. if one of the zeroes of the equation is 4, what is the other zero?
FinnZ [79.3K]
ANSWER

The other zero is

x =  - 10

EXPLANATION

The axis of symmetry serves as the midpoint of the two zeroes.


We were given that the axis of symmetry of the quadratic equation is
x =  - 3


We were also given that, one of the zeroes of the quadratic equation is
x = 4


Let the other zero of the quadratic equation be
x = p

,then, we apply the midpoint formula to find the value of
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Since it is the x-values of the intercepts that gives the solution, we use only the x-value part of the midpoint formula which is given by,




\frac{x_1 + x_2}{2}  = axis \: of \: symmetry

We substitute to obtain,

\frac{p + 4}{2}  =  - 3



We multiply through by 2 to get,

p + 4 =  - 6



This implies that,

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3 0
3 years ago
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Kamila [148]
I hope this helps you




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ikadub [295]

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