A=g
v=⌠g dt
v=gt+C, where C=v initial
v=gt+vi
h=⌠v dt
h=gt^2/2+vit+C, where C=h initial
h=gt^2/2+vit+hi
We are told that vi=42 ft/s, hi=0, and we know g≈-32 ft/s^2 so
h(t)=-16t^2+42t
The ball will hit the ground when h=0 so
-16t^2+42t=0
-2t(8t-21)=0, since t>0
8t-21=0
8t=21
t=21/8
t=2.625 sec
t≈2.6 sec (to nearest tenth of a second)
Answer:
Distribute -4 to a and -5
Step-by-step explanation:
Trust me it is correct
Good luck:)
9514 1404 393
Answer:
k = 7
m = 8
Step-by-step explanation:
The diagonals bisect each other, so each half is equal to the opposite half.
k +4 = 11 . . . . down-sloping diagonal
k = 7
__
m = 8 . . . . up-sloping diagonal
