Let W = width of package
Let H = height of package
Let L = length of package
The perimeter cab be one of the following:
P = 2(L + W), or
P = 2(L + H)
The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
2(L + 10) <= 108
L + 10 <= 54
L <= 44 in
When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in
To satisfy both of these conditions requires that L <= 39 in.
Answer: 39 inches
Answer:
10.5
Step-by-step explanation:
Break the problem down into small parts:
2 to the power of 3= 8
8+7+6=
15+6=21
21/2
21 divided by 2 is 10.5
Hope this helps!
Answer:
(5(x-4))0
evaluate
1
Step-by-step explanation:
your answer is one i believe
First of all, remember what the equation of a line is:
Where:
m=slope
b=y-intercept.
Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope
To find b, think about what your (x,y) point means:<span>(14,3). When x of the line is 14, y of the line must be 3.
Because we were given the point (14,3)
</span>
We need to find the value of b. The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).
<span>Plug in for x the number 14 and for y the number 3:
</span>(14,3).
y=mx+b or 3=2 × 14+b,
solving for b: b=3-(2)(14). b=-25.
<span>Plug that in for b:
</span><span>y=2x-25
<span>Final answer:
</span><span>y=2x-25</span></span><span><span>
</span></span>
Not possible, we can't answer the question if we can't see the dimensions.
#BestAnswer
