Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B
1 ft = 12 inches....so 4 ft = (4 * 12) = 48 inches
ratio is : 48 to 15...or 48/15 or 48:15......which reduces to 16/5 in lowest terms
Answer:
4x= 40
mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Answer:
Step-by-step explanation:
Draw a horizontal line at the end of the 8 meter horizontal line.
Find the area of the horizontal rectangle
L = 8 + 3
W = 2
Area = L*w
Area = 11*2
area = 22 m^2
Now do the vertical rectangle
L = 8
w = 3
Area = L*w
Area = 8 * 3
Area = 24 m^2
Total Area = 24 + 22 = 46 m^2
The greatest common factor is 4r so
4r(d-4)