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kozerog [31]
4 years ago
15

5x- 1 >8x+23 what would the inequality be

Mathematics
1 answer:
Lynna [10]4 years ago
8 0
Olá

5x-1>8x+23

5x-8x>23+1

-4x>24

4x<-24

x<-24/4

x<-6
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Find the equation for a parabola that has a vertex at (0, 4) and passes through the point (–1, 6). a) y=2(x-1)^2+6 b) y=2x^2-6 c
docker41 [41]
The answer is D because the answers are put into vertex form and all you have to do is look at your (h,k) values
4 0
3 years ago
2 Solve the equation for t. Show your work.<br> 5(2t - 3) – 7.5t = 0.5(12 – t)<br> PLEASEEEE HELP ME
dsp73

Answer:

t = 7

Step-by-step explanation:

5(2t - 3) – 7.5t = 0.5(12 – t)

5*2t - 3*5 - 7.5t = 12*0.5 - t *0.5

10t - 15 - 7.5t = 6 - 0.5t           {Now, combine like terms}

10t - 7.5t - 15 = 6 - 0.5t

         2.5t -15 = 6 - 0.5t      {Add 15 to both sides}    

         2.5t      = 6 - 0.5t + 15

              2.5t = 21 - 0.5t       { Add 0.5t to both sides}

    2.5t + 0.5t = 21  

                 3t = 21     {Divide both sides by 3}

                   t = 21/3

t = 7

6 0
3 years ago
If d=3 what is the answer? 7b to the power of three +10
Sati [7]

Answer:

199 if it's 7b^3 + 10

9271 if it's (7b)^3 + 10

Step-by-step explanation:

You just substitute the 3 in for d. If your expression was 7b^3 + 10, then only b is being raised to 3.

So 3^3 is 27, 27*7 is 189, 189+10 is 199.

If the expression was (7b)^3 + 10, then first you multiply 7 and 3 to get 21. Then you raise 21 to the power of 3, which is 9261. Then you add 10, which is 9271.

7 0
3 years ago
Find the number of positive numbers less than 2020, which can not be written as the sum of six consecutive positive numbers.
sveta [45]

Answer: 334

Step-by-step explanation:

6 consecutive numbers can be written as:

n, n+1, n+2, n + 3, n + 4, n + 5,

The addition of those 6 numbers is:

n + n+1 + n+2 + n + 3 + n + 4 + n + 5

6n + 1 + 2 + 3 + 4 + 5 = 6n + 15

Let's find the maximum n possible:

6n + 15 = 2020

6n = 2020 - 15 = 2005

n = 2005/6 = 334.16

The fact that n is a rational number means that 2020 is can not be constructed by adding six consecutive numbers, but we know that with n = 334 we can find a number that is smaller than 2020, and with n = 335 we can found a number bigger than 2020.

So with n =  334 we can find one smaller.

6*334 + 15 = 2019

and we can do this for all the values of n between 1 and 334, this means that we have 334 numbers less than 2020 that can be written as a sum of six consecutive positive numbers.

8 0
3 years ago
ANYONE KNOW THIS???????
anyanavicka [17]

Answer:

cant read

Step-by-step explanation:

6 0
3 years ago
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