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Sever21 [200]
4 years ago
11

How many mil to cover a 16×20 canvas​

Mathematics
2 answers:
Anon25 [30]4 years ago
8 0
320 is your answer!
faltersainse [42]4 years ago
5 0

Answer:320


Step-by-step explanation:


You might be interested in
Given the system of linear equations.
Karo-lina-s [1.5K]

Part A:


x + y = 9

4x + y = 6


To solve this system using substitution, begin by isolating either x or y in the first equation. I'll isolate x.


x + y = 9

x = 9 - y


Substitute this expression (9 - y) into the second equation for x and solve.


4x + y = 6

4(9 - y) + y = 6

36 - 4y + y = 6

36 - 3y = 6

-3y = -30

y = 10


To find x, substitute 10 for y into either of the original equations.


x + y = 9

x + 10 = 9

x = -1


Finally, check all work by substituting the x- and y-values into each original equation.


x + y = 9   -->   -1 + 10 = 9   -->   9 = 9   -->   True

4x + y = 6   -->   4(-1) + 10 = 6   -->   -4 + 10 = 6   -->   6 = 6   -->   True


The answer for Part A is x = -1 and y = 10; (-1, 10).


Part B:


For graphing, it's easier to get the equations into slope-intercept form. Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. To get our equations into slope-intercept form, we must simply isolate y.


x + y = 9

y = 9 - x

y = -x + 9


4x + y = 6

y = 6 - 4x

y = -4x + 6


Now that we have our slope-intercept equations, we can easily graph them, since their slopes and y-intercepts are readily visible.



Let's start with the y-intercepts. They are (0, 9) and (0, 6). You can plot those points on the graph.


Now, the slopes. The slope of the first line is -1, this means it declines. To plot this, start where you plotted the y-intercept, count one unit down, and then one unit to the right, and plot that point. Continue doing that and connect the dots, and you will have plotted the first line. The slope of the second line is -4, so it also declines. For this line, count four units down, and then one to the right and plot that point. Likewise, continue this and connect the coordinates, and you will have your line. (See attachment for graph.)


The lines do indeed intersect at (-1, 10); our answer is verified by graphing.

5 0
3 years ago
50+x(greater than or equal to)300
nikdorinn [45]

Answer:

x ≥ 250

Step-by-step explanation:

Note that "greater than or equal to" looks like ≥

50 + x ≥ 300

Isolate the variable. What you do to one side, you do to the other. Subtract 50 from both sides.

x + 50 (-50) ≥ 300 (-50)

x ≥ 300 - 50

x ≥ 250

x ≥ 250 is your answer.

~

4 0
3 years ago
Is -8 an irrational number?<br> yes or no
kherson [118]

no bc it is not no no no no no no no

3 0
3 years ago
The diameter of a cylindrical construction pipe is7ft. If the pipe is 36ft long, what is its volume?
Svetradugi [14.3K]

Question:

The diameter of a construction pipe is 7ft. If the pipe is 35ft long, what is the volume. (Use 3.14 for pie and round your answer to the nearest cubic foot.)

Answer: V=pir^2h V=3.14*3.5^2*35 V=1346 cu ft

Not fully sure....

But it should be right...

6 0
2 years ago
9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat
Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 2000, p = 1-0.995 = 0.005

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

P(X < 5) + P(X \geq 5) = 1

We want P(X \geq 5)

So

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044

P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445

P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235

P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480

P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765

P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0
3 years ago
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