The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:
the shaded area is 26, the non-shaded area 16
Step-by-step explanation:
The red shaded lines had numbers as well so I add all of them up.
The non-shaded lines didn't have a number, but the bottom had the same length of the top line so therefore your answer is 26 for Shaded, and 16 for non-shaded.
Answer:
≤ Note: without the equal
Step-by-step:
√7 =2.645
14/5 = 2.8
Answer:
Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.
Step-by-step explanation:
From given scatter plot, we see that upper quartile of Mrs. Cai's class = 4
lower quartile of Mr. Roland’s class = 4
Both are equal so that means.
That means Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.
Hence last choice is correct.
Let P(a, b) be a point on the coordinate plane. Then the following hold:
i) If a>0, b>0 then P is in the I.Quadrant.
ii) If a<0, b>0 then P is in the II.Quadrant.
iii) If a<0, b<0 then P is in the III.Quadrant.
iv) If a>0, b<0 then P is in the IV.Quadrant.
v) If a=0 and b is positive or negative, then P is on the y-axis.
vi) If b=0 and a is positive or negative, then P is on the x-axis.
Since we have: a=0, and 19 positive, then this point is on the y-axis.
Answer: y-axis
