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3 years ago

Write Three and eight thousandths in standard form? What is it

Mathematics

1 answer:

Lapatulllka [165]3 years ago

6 0

Thousandths is the 3rd decimal place

The answer is 3.008

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PLEASE HELP (100 POINTS)

Artyom0805 [142]

$\\ \rm\Rrightarrow f(x)=-5cos\dfrac{x}{2}+5$

Compare to standard equation of SHM

$\\ \rm\Rrightarrow y=Acos(\omega x+\phi)$

Here

Amplitude=A=-5

$\\ \rm\Rrightarrow \omega x=\dfrac{x}{2}$

$\\ \rm\Rrightarrow \omega=1/2$

Well the above one are for extra knowledge .

Solution:-

$\\ \rm\Rrightarrow 10=-5cos\dfrac{x}{2}+5$

$\\ \rm\Rrightarrow 10-5=-5cos\dfrac{x}{2}$

$\\ \rm\Rrightarrow 5=-5cos\dfrac{x}{2}$

$\\ \rm\Rrightarrow cos\dfrac{x}{2}=-1$

$\\ \rm\Rrightarrow \dfrac{x}{2}=cos^{-1}(-1)$

$\\ \rm\Rrightarrow \dfrac{x}{2}=\pi$

$\\ \rm\Rrightarrow x=2\pi$

So.

$\\ \rm\Rrightarrow x=2\pi+2\pi n$

3 0

2 years ago

Read 2 more answers

Using the method of completing the square, put each circle into the form

tatiyna

Answer:

Standard form: $(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Center: $(\frac{1}{2}, 0)$

Radius: $r =\sqrt{15}$

Step-by-step explanation:

The equation of a circle in the standard form is

$(x-h)^{2} + (y-k)^{2} = r^{2}$

Where the point (h, k) is the center of the circle

To transform this equation $4x^{2} -4x + 4y^{2} - 59 = 0$ this equation in the standard form we use the method of square.

First, we group similar variables

$(4x^{2} -4x) + (4y^{2}) - 59 = 0$

Divide both sides of equality by 4

$(x^{2} -x) + (y^{2}) - 14.75 = 0$

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

$b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2= (-\frac{1}{2})^2 = \frac{1}{4}$

Now add $(\frac{b}{2})^2$ on both sides of the equality

$(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})$

Factor the expression and simplify the independent terms

$(x-\frac{1}{2})^2 + (y^{2}) = 15$

$(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Then

$h =\frac{1}{2}\\\\k=0$

and the center is $(\frac{1}{2}, 0)$

radius $r =\sqrt{15}$

3 0

3 years ago

How do i do -7x-3x+2=-8x-8

dexar [7]

Answer: 5

Step-by-step explanation:

-7x-3x+2=-8x-8

-10x+2=-8x-8

-10x+8x=-8-2

-2x=-10

x=-10/-2

x=5

8 0

3 years ago

Pls show all work. I will mark BRAINLIEST. Plsssss thank you and will the to give as many points. Answer has to be right. Due 11

dimulka [17.4K]

Answer: N0. There are not enough teacher signatures.

<u>Step-by-step explanation:</u>

Total signatures needed: $\frac{1}{8}$ x 1200 = 150

Total signatures received: 150

********************************************************************

Teacher signatures needed: $\frac{1}{25}$ x 150 = 6

Teacher signatures received: $\frac{2}{75}$ x 150 = 4

<em>Side note: If there are $\frac{73}{75}$ student signatures then there are $\frac{2}{75}$ teacher signatures, because the student plus teacher signatures must equal 100%</em>

8 0

3 years ago

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An animal shelter has 4/5 of its crates filled with animals. 1/2 of the filled crates are holding cats. What fraction of the tot

max2010maxim [7]

8/10s of the crates are filled with animals, half of those are holding cats so 4/10s are holding cats so I believe 4/10s of the total crates are holding cats

5 0

3 years ago

Read 2 more answers