Answer:
Circle
Explanation:
When a charged particle is in motion in a region with magnetic field, the particle experiences a force whose magnitude is given by
where
q is the charge
v is the velocity of the particle
B is the strength of the magnetic field
is the angle between the directions of v and B
In this problem, the velocity of the particle is perpendicular to the magnetic field, so
and the formula reduces to
Also, the direction of this force is perpendicular to the direction of motion of the particle. This means that as the charge moves in the region of the magnetic field, the force acting on it acts as a centripetal force: therefore, the particle will start moving by unifom circular motion, with constant speed (because the magnetic force does no work on the particle, since it is perpendicular to the direction of motion).
So, the path of the particle will be a circle.
Answer:
Explanation:
Given that,
Hot reservoir temperature is
TH = 58°C
TH = 58 + 273 = 331 K
Cold reservoir temperature
TC = -17°C
TC = -17°C + 273 = 256K
In 24minutes 590 J of heat was removed from hot reservoir
t = 24mins
t = 24 × 60 = 1440 seconds
Then,
Power is given as
P = E / t
P = 590 / 1440
P = 0.41 W
Since this removed from the hot reservoir, then, QH = 0.41W
We want to find heat expelled to the cold reservoir QX
Efficiency is given as
η = 1 - TH/TC = 1 - QH/QC
1 - TH/TC = 1 - QH/QC
TH/TC = QH/QC
Make QC subject of formula
QC = QH × TC / TH
QC = 0.41 × 256 / 331
QC = 0.317 W
Answer:
The additional force is
Explanation:
From the question we are told that
The horizontal force in one direction is
The horizontal force in the opposite direction is
The negative sign shows that it is acting in the opposite direction
Generally for the box to remain stationary the net force on it must be equal to zero that is
Where is the additional force required
So
substituting values
Answer:
15.Radiowave
16.laser is device that generates an intense beam of other electromagnetic radiation by emission of photons from excited atoms.
17.this is a laboratory instrument commonly used to display and analyse the waveformof electronic signals.
19. this is a space entirely devoid of matter.
Answer:
The value is
Explanation:
From the question we are told that
The mass of the external weight is
The height through which the mass drops is
The number of revolution made is
The diameter of the free moving piston is
The distance moved by the free moving piston is
The atmospheric pressure is
Generally the workdone by the external weight is mathematically represented as
=
=
Generally the workdone by the free moving piston is mathematically represented as
Here A is the cross-sectional area with value
So
=>
So
The net workdone is mathematically evaluated as
The negative sign shows that it is acting in opposite direction to
So