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4 years ago

ALGEBRA 2! Please help with question 2!!!

Mathematics

1 answer:

nlexa [21]4 years ago

3 0

Answer:

√x

Step-by-step explanation:

First and foremost, simplify -3⁄6, which is -½. Now, according to the negative exponential rule, move -½ to the numerator while ALTERING THE INTEGER SYMBOL FROM NEGATIVE TO POSITIVE:

bⁿ = 1\b⁻ⁿ

This will become x¹\². Then, you will need to use the definition of rational exponents [part I] rule to rewrite this rational exponent as a radical. This is when your numerator is 1:

ⁿ√aᵐ = aᵐ\ⁿ → x¹\² >> √x [unnecessary to write the 1 and 2]

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

**In one of my You-Tube videos, it talks about all the six exponential rules. It is titled "Six Exponential Procedures". I encourage you to watch it, so you can get better at it.

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What function is depicted in the graph above

vesna_86 [32]

Answer:

what graph show me the graph

Step-by-step explanation:

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3 years ago

Which graph shows the solution to the following system? y= 1/4x - 2

iogann1982 [59]

Y = 1/4 x - 2

=> a linear function => a straigh line

=> slope = the coefficient of x => slope = 1/4

=> x = 0 => the y-intercept = -2

=> y = 0 => 0 = 1/4 x - 2 =>x = 8 => point (8,0)

With all that information you can identify the graph because it is a straight line that passes through (0,-2) and (8,0), its inclination (slope) is 1/4, and the graph goes through the quadrants I, III and IV (there are no points in the quadrant II)..

4 0

3 years ago

When s is the open hemisphere x 2 + y 2 + z 2 = 1, z ≤ 0 , oriented by the inward normal pointing to the origin, then the bounda

Anit [1.1K]

The figure below shows a diagram of this problem. First of all we graph the hemisphere. This one has a radius equal to 1. Given that z ≤ 0 a sphere will be valid only in the negative z-axis, that is, we will get a half of a sphere that is the hemisphere shown in the figure. We know that this hemisphere is oriented by the inward normal pointing to the origin, then we have a Differential Surface Vector called N, using the Right-hand rule the boundary orientation is counterclockwise.

Therefore, the answer above False

5 0

4 years ago

The formulas for power and work are and , where P= w/t is the power, W= fd

Klio2033 [76]

P = W/t
W = Fd

P = Fd/t = F/t d

6 0

4 years ago

Read 2 more answers

3.Original DNA sequence: 3' TACCGCTTACGTCTGATCGCT 5'

sdas [7]

3. The original sequence

TAC - CGC - TTA - CGT - CTG - ATC - GCT

codes for

tyr - arg - leu - arg - leu - ile - ala

while the mutated sequence codes for

TAC - CGC - TTA - TTA - TTA - CGT - GCT - GCT - ATC - GCT

tyr - arg - leu - leu - leu - arg - ala - ala - ile - ala

There are several frameshift mutations involved here:

• the first inserts 6 bases (TTA - TTA)

• the second inserts 1 base (G) before the CTG triplet (underlined)

• the third inserts 2 bases (CT) after the CTG triplet

4. The original sequence is the same as before. The mutated sequence

TAC - CGC - TAA - TTA - TTA - CGT - GCT - GCT - ATC - GCT

codes for

tyr - arg - STOP - leu - leu - arg - ala - ala - ile - ala

Then

• there is a (nonsense) point mutation that swaps T for A in the original TTA triplet (nonsense since it produces a stop codon that would halt replication/expression)

• there is a frameshift mutation that inserts 3 bases (TTA)

as well as two other frameshift mutations that also occurred in the previous part.

7 0

3 years ago