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Veseljchak [2.6K]
4 years ago
9

If the random variable X is normally distributed with a mean of 75 and a standard deviation of 8, then P(X ≥ 75) is:a. 0.500b. 0

.250c. 0.125d. 0.975e. 0.625
Mathematics
1 answer:
drek231 [11]4 years ago
5 0

Answer:

a. 0.5

Step-by-step explanation:

We know that X follows normal distribution with

mean=75

standard deviation=8

P(X\geq 75)=P(\frac{x-mean}{standard deviation}\geq \frac{75-75}{8})

P(X\geq 75)=P(Z\geq 0)

P(Z\geq 0)=P(0<Z<∞)

The area under the normal curve is 1 and the  (0<Z<∞) =0.5 and (-∞<Z<0) =0.5

So, P(0<Z<∞)=0.5

Hence the P(X ≥ 75)=0.5

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Element X decays radioactively with a half life of 10 minutes. If there are 120 grams of Element X, how long, to the nearest ten
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49.1 minutes

Step-by-step explanation:

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The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15
Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7       Grade 8

  20                  21

  15                  29

  30                  14

  24                  19

   18           24

   21                 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24

The interquartile range for the grade 7 data is

IQR=Q_3-Q_1=24-18=6

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25

The interquartile range for the grade 8 data is

IQR=Q_3-Q_1=25-19=6

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

D=22.5-20.5=2

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

D=x(IQR)

2=x(6)

\frac{2}{6}=x

\frac{1}{3}=x

Therefore the difference is about 1/3 times the interquartile range of either data set.

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A line passes through (1, - 1) and (3, 5). What is the equation of the line in slope-intercept form?​
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Step-by-step explanation:

If you find a solution to these equations, you will find an equation of your line. Please notice that (a,b,c) defines the same line as (ka,kb,kc) and for any non-zero k, and a=b=c=0 defines no line equation at all. Now you can take a=1 and solve for b and c, or take b=1 and solve for a and c, or take c=1 and solve for a and b, at least one of these will work.

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Step-by-step explanation:

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Step-by-step explanation:

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