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KonstantinChe [14]
3 years ago
15

What is the solution to the system of equations? (7, 9) (9, 7) (–5, 11) (11, –5)

Mathematics
1 answer:
KIM [24]3 years ago
6 0

Answer: (7, 9)

Step-by-step explanation: To solve this system, I would use addition.

To solve a system of equations by addition,

we need one of our variables to cancel out.

Notice that we have a 4x in our first equation.

If we had a -4x in our second equation, the x's would cancel.

To create a -4x in the second equation,

we must multiply the entire equation by -4.

So we have (-4)(x + 6y) = (61)(-4).

Rewriting this equation, we have -4x - 24y = -244.

Now let's rewrite both equations.

<h2>4x - 5y = -17</h2><h2>-4x - 24y = -244</h2><h2>_____________</h2><h2 />

Now when we add the equations together, the x's cancel.

So we're left with -29y = -261.

Now divide both sides by -29 and we have y = 9.

To find x, we plug a y back in for x in either equation.

So let's go with our second equation, x + 6y = 61.

Plugging a 9 in for y, we have x + 6(9) = 61 or x + 54 = 61.

Subtracting 54 from both sides, we have x = 7.

So x = 7 and y = 9 which we can write as the ordered pair (7, 9).

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Step-by-step explanation:

By putting all of the numbers in numerical order, then adding them and dividing them by 11 (the number of numbers in the list), you get 33.45 repeating as the mean. With the organized list of numbers find the middle number, which is 35, and that is the median. The mode, the most common number in the sequence, is 37 and 25.

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The y-axis of a cartesian plane is the same as the equation x = 0 (that is, the collection of all points with an x-coordinate of 0.)

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\begin{aligned}\begin{cases} y = x^{2} + x - 6 & \text{for the quadratic function} \\ x = 0 & \text{for the $y$-axis}\end{cases}\end{aligned}.

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\begin{aligned}\begin{cases} x = 0 \\ y = -6\end{cases}\end{aligned}.

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