Answer:
public static String repeat(String text, int repeatCount) {
if(repeatCount < 0) {
throw new IllegalArgumentException("repeat count should be either 0 or a positive value");
}
if(repeatCount == 0) {
return "";
} else {
return text + repeat(text, repeatCount-1);
}
}
Explanation:
Here repeatCount is an int value.
at first we will check if repeatCount is non negative number and if it is code will throw exception.
If the value is 0 then we will return ""
If the value is >0 then recursive function is called again untill the repeatCount value is 0.
Answer:
In Python:
def fib(nterms):
n1, n2 = 1, 1
count = 0
while count < nterms:
term = n1
nth = n1 + n2
n1 = n2
n2 = nth
count += 1
return term
Explanation:
This line defines the function
def fib(nterms):
This line initializes the first and second terms to 1
n1, n2 = 1, 1
This line initializes the Fibonacci count to 0
count = 0
The following while loops gets the number at the position of nterms
<em> while count < nterms:
</em>
<em> term = n1
</em>
<em> nth = n1 + n2
</em>
<em> n1 = n2
</em>
<em> n2 = nth
</em>
<em> count += 1
</em>
This returns the Fibonnaci term
return term
