Well what is the problem ?
Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.


Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as

by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because

is a polynomial).
Answer:
{6,7,8,9,10}
Step-by-step explanation:
Solve the inequality using inverse operations.

This solution means values equal to or larger than 6 from the set are solutions. This means 6, 7, 8, 9, and 10 are the solution set.
Shelby mistake is 11;4 is not the correct mixed number
Answer:
From largest to smallest: FG, FH, GH
Step-by-step explanation:
Given




Required
Order the sides in descending order
First, we need to solve for x.
Perimeter of FGH is calculated as thus:

Substitute values for FG, GH, FH and Perimeter

Collect Like Terms


Reorder

Divide through by 24


Substitute 4 for x in FG, GH and FH












In order of arrangement in descending order, we have:
