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3 years ago

Estimate the square root of 25. Round to the nearest hundredths place. Show your work!

Mathematics

1 answer:

IRISSAK [1]3 years ago

3 0

Answer:

5.00

Step-by-step explanation:

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Erin found 9 cents<br> each day for 7 days.<br> How much money did<br> she find in all?

kherson [118]

After 7 days she would have eventually found 63 cents.

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3 years ago

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The life expectancy (in hours) of an electric bulb is normally distributed with a mean of 5000 and a standard deviation of 1000.

Sergeu [11.5K]

Answer:

P(z>1.3) = 0.9032

Step-by-step explanation:

We are given:

Mean = 5000

Standard deviation = 1000

x = 6300

P(x>6300)=?

z-score =?

z-score = x- mean/standard deviation

z-score = 6300 - 5000/1000

z- score = 1300/1000

z-score = 1.3

So, P(x>6300) = P(z>1.3)

Looking at the z-probability distribution table and finding value:

P(z>1.3) = 0.9032

So, P(z>1.3) = 0.9032

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4 years ago

A tin is a right circular cylinder with a diameter of 6 meters and a height of 10 meters. What is the surface area of this tin,

Alex777 [14]

Answer:

245.04

Step-by-step explanation:

A=2πrh+2πr2=2·π·3·10+2·π·32≈245.04423

Divide 6 by 2 to find the radius

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3 years ago

Simplify the expression 2x+x+x

anyanavicka [17]

If you combine like terms the answer is 4x

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3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago