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3 years ago

If this the midpoint and st=x+3 and tu=4x-6 what is st and su

Mathematics

1 answer:

iragen [17]3 years ago

3 0

Answer:

st = 6

su = 12

Step-by-step explanation:

t is the midpoint of line segment su.

st = x + 3

tu = 4x - 6

Since, t is the midpoint of su, it should divide su into two equal parts. This means, measure of st and tu would be equal. So,

st = tu

x + 3 = 4x - 6

3 + 6 = 4x - x

9 = 3x

x = 3

st = x + 3 = 3 + 3 = 6

tu = 4x - 6 = 4(3) - 6 = 6

su = st + tu = 6 + 6 = 2(6) = 12

So, the measure of st would be 6 units and measure of su would be 12 units.

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jason wants to choose 9 players for his track team ,there are 12 players to choose from.how many different teams can jason make?

mote1985 [20]

He could only make one team, considering that if you do 12-9, you are left with 3, and Jason wants to have his team consisted of 9 players. However, if you make 3 teams with 4 players on each team, or 4 teams with 3 players on each team, you could do that as well.

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3 years ago

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Find the number of tiles required to be put in a floor with dimensions 25 m x 20 m. Each tile is a rhombus with side 25 cm altit

Romashka-Z-Leto [24]

Answer:

8000

Step-by-step explanation:

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2 years ago

Which expressions have a sum of -12 right answer only!!

kenny6666 [7]

Answer:

B and D

Step-by-step explanation:

2+-14 = -12

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3 years ago

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A farmer has 120 feet of

sergejj [24]

Answer: D) Length: 60, Width: 30

Step-by-step explanation:

The totals of the length plus two widths of the other dimensions given do not add up to 120 feet.

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3 years ago

For the region bounded by y=2x, the x-axis, and x=1, determine which of the following is greater: the volume of the solid ge

telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

$\int\limits^1_0 {(pi)y^{2} } \, dx$

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

$\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy$

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

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3 years ago