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GenaCL600 [577]
3 years ago
7

If f(x)=(x^2-2x-1)^2/3, then f'(0) is?

Advanced Placement (AP)
1 answer:
MakcuM [25]3 years ago
3 0
F'(x)=(2/3(x^2-2x-1)^-1/3 )*(2x-2) chain rule here

f'(0) is equals to substitute x with 0. Which gives

f'(0)= (2/3(-1)^-1/3)*(-2)

Plug in the calculator, and your answer is ready
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