3 years ago

If f(x)=(x^2-2x-1)^2/3, then f'(0) is?

1 answer:

3 0

F'(x)=(2/3(x^2-2x-1)^-1/3 )*(2x-2) chain rule here

f'(0) is equals to substitute x with 0. Which gives

f'(0)= (2/3(-1)^-1/3)*(-2)

Plug in the calculator, and your answer is ready

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