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Elenna [48]
3 years ago
8

D-c/pie solve for pie

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0
With a little algebraic manipulation we can solve for pi...

d-c / pi

we want to get pi by itself so first we multiply both sides by pi to get it out of the denominator...

pi × (d-c) = pi / pi
pi × (d-c) = 1

Now get pi by itself by dividing both sides by d-c...

pi × (d-c) / d-c = 1 / d-c

simplify

pi × 1 = 1 / d-c
pi = 1 / d-c

Done!
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In how many distinct ways can the 11 letters in engineering be arranged
SVEN [57.7K]
The answer is >>> 4 989 600
6 0
3 years ago
The time to complete the construction of a soapbox derby car is normally distributed with a mean of three hours and a standard d
TEA [102]

Answer:

The probability that it would take more than four hours to construct a soapbox derby car = 0.1587 or 15.87\%

Step-by-step explanation:

Given -

Mean (\nu )  = 3 hours

Standard deviation (\sigma  ) = 1 hours

Let X be the no of hours to construct a soapbox derby car

the probability that it would take more than four hours to construct a soapbox derby car =

P(X > 4)  = P(\frac{X - \nu }{\sigma}> \frac{4 - 3 }{1})

                = P(Z > 1)                   Put (Z = \frac{X - \nu }{\sigma})

                 =  1 -  P(Z <  1)            

                 =  1 - .8413                    Using z table

                  = 0.1587

3 0
3 years ago
PLEASEEEEEE HELPPPPPPPP
Natali5045456 [20]
The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:

S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
The answer is A.
8 0
3 years ago
Let A and B be two events in a sample space S such that
klasskru [66]
P(A|B)<span>P(A intersect B) = 0.2 = P( B intersect A)

</span>A) P(A intersect B) = <span>P(A|B)*P(B)
Replacing the known vallues:
0.2=</span><span>P(A|B)*0.5
Solving for </span><span>P(A|B):
0.2/0.5=</span><span>P(A|B)*0.5/0.5
0.4=</span><span>P(A|B)
</span><span>P(A|B)=0.4
</span>
B) P(B intersect A) = P(B|A)*P(A)
Replacing the known vallues:
0.2=P(B|A)*0.6
Solving for P(B|A):
0.2/0.6=P(B|A)*0.6/0.6
2/6=P(B|A)
1/3=P(B|A)
P(B|A)=1/3
5 0
3 years ago
Solve for p P-17=2p+3
Y_Kistochka [10]

Answer:

-20

Step-by-step explanation:

P-17=2P+3

P-2P=17+3

-P=20

Divide both sides by negative 1

P=20

7 0
3 years ago
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