Negative 8(3y divide by 5) minus 5 Simplify the expression
1 answer:
You might be interested in
Answer:
A. Domain : (-∞, ∞)
B. Function is increasing in the interval (-2, 0) and (2, ∞)
Decreasing in the interval of (-∞, -2) and (0, 2).
Step-by-step explanation:
A. Given function is, y = |2x - 1|
This function is the transformed form of the parent function, y = |x|
Domain of the parent function is { x | x is a set of real numbers}
Therefore, domain of the transformed function will be the same as the domain of the parent function.
Domain of the function = {x | x is a real number}
B. Given function is f(x) =
Domain of the function : (-∞, ∞)
Critical points of the function are,
⇒ x = 0, ±2
Now we find the three intervals where we have to check the function to be increasing or decreasing.
(-∞ -2), (-2, 0), (0, 2), (2, ∞)
Derivative of the function f(x),
f'(x) =
Here, f'(x) < 0 for (-∞, -2)
f'(x) > 0 for (-2, 0)
f'(x) < 0 for (0, 2)
f'(x) > 0 for (2, ∞)
Therefore, given function is increasing in the interval (-2, 0) and (2, ∞)
And it's decreasing in the interval of (-∞, -2), and (0, 2).
